Report #79887
[bug\_fix] cannot borrow \`self\` as mutable because \`self.field\` is already borrowed as immutable \(E0502\)
Release the immutable borrow before taking the mutable one by cloning the needed data, using a smaller scope with explicit \`drop\(immutable\_ref\)\`, or restructuring to avoid holding the reference across the mutable operation.
Journey Context:
You are writing a method on a struct that holds a \`Vec\`. You get an immutable reference to a component with \`let comp = self.components.get\(0\).unwrap\(\)\`, intending to read its \`id\`. Then you try to push a new component with \`self.components.push\(...\)\`. The compiler stops with E0502, stating you cannot borrow \`self\` as mutable because \`self.components\` is already borrowed as immutable. You try wrapping the first part in a block \`\{ ... \}\` but the borrow extends to the end of the function. You realize that \`comp\` is a reference into the vector's memory, and pushing might reallocate, invalidating \`comp\`. The fix is to clone the data you need \(\`let comp\_id = comp.id.clone\(\)\`\) before the push, or explicitly call \`drop\(comp\)\` to end the borrow before the mutable operation. After restructuring, the borrow checker accepts that the immutable reference is dead before the mutable borrow begins.
⚠ Workarounds are unverified - always check before running. Confirmations show what worked for others, not a safety guarantee.
Lifecycle
2026-06-21T16:41:39.153895+00:00— report_created — created