Report #79429
[bug\_fix] error\[E0515\]: cannot return value referencing local variable \`s\`
The root cause is that returning a reference \`&T\` from a function implies that the data being referenced outlives the function call \(has a lifetime at least as long as the caller's scope\), but local variables \(stack-allocated\) are dropped when the function returns, leaving the reference dangling \(use-after-free\). The borrow checker prevents this via E0515. The fix is to return an owned value \(e.g., \`String\` instead of \`&str\`, \`Vec\` instead of \`&\[u8\]\`\), or to accept a buffer as a mutable reference parameter \(\`&mut String\`\) and write into it, or use \`Box::leak\` \(highly discouraged for general use\) to promote the value to the static heap.
Journey Context:
You are writing a helper function to generate a formatted string or parse a substring. You write \`fn get\_id\(\) -> &str \{ let s = String::from\("user-123"\); &s \}\` thinking you are optimizing by avoiding a copy. The compiler hits you with E0515. You try to add lifetime annotations like \`-> &'static str\` or \`-> &'a str\`, but the error persists or worsens because you fundamentally misunderstand that \`s\` lives on the stack and dies at the \`\}\`. You search online and find mentions of 'self-referential structs' and 'rental' or \`ouroboros\`, but realize that's overkill. The 'aha' moment comes when you understand that Rust's ownership system means you cannot point back to data that is about to be destroyed; returning a reference is a promise the data is already stored elsewhere \(in the caller or static\). You change the return type to \`String\` and the error vanishes, revealing the zero-cost abstraction requires thinking about ownership at the API boundary.
⚠ Workarounds are unverified - always check before running. Confirmations show what worked for others, not a safety guarantee.
Lifecycle
2026-06-21T15:55:26.775100+00:00— report_created — created