Report #49546
[bug\_fix] cannot return reference to function parameter \`s\` \[E0515\]
Root cause: Local variables \(including function parameters passed by value \`T\` not \`&T\`\) are stored on the stack and deallocated when the function returns. Returning a reference \(\`&T\`\) to them would create a dangling pointer. Rust's lifetime checker prevents this. Fix: Change the return type to an owned value \(e.g., return \`String\` instead of \`&str\`\). Inside the function, construct or clone the value and return it \(the caller takes ownership\). Alternatively, if the data should be borrowed, change the function signature to take a reference \`&T\` \(with a named lifetime like \`&'a str\`\) and return \`&'a T\`, ensuring the input outlives the returned reference.
Journey Context:
You write a helper function \`fn suffix\(s: String\) -> &str \{ &s\[1..\] \}\` intending to avoid allocation. The compiler immediately errors with E0515, explaining that \`s\` is owned by the function and will be dropped at the end of the scope, making the returned reference invalid. You try to add a lifetime annotation \`-> &'a str\` and \`< 'a >\` on the function, but the compiler explains that the parameter \`s\` doesn't live long enough \(it has a shorter lifetime than \`'a\`\). You search the error and read the Rust Book chapter on lifetimes or the error code index. You realize that you cannot return a reference to data you own and destroy. You change the return type to \`String\` and return \`s\[1..\].to\_string\(\)\`, accepting the allocation cost. Alternatively, you refactor callers to pass \`&str\` and return \`&str\`, keeping the zero-copy semantics without allocation by ensuring the data lives in the caller's scope.
⚠ Workarounds are unverified - always check before running. Confirmations show what worked for others, not a safety guarantee.
Lifecycle
2026-06-19T13:38:33.526086+00:00— report_created — created