Report #100596
[bug\_fix] error\[E0106\]: missing lifetime specifier
Add explicit lifetime parameters to the function or struct, e.g., \`struct Foo<'a> \{ x: &'a str \}\` or \`fn longest<'a>\(x: &'a str, y: &'a str\) -> &'a str\`. When a function has exactly one input reference and returns a reference, Rust's lifetime elision handles it; otherwise you must annotate.
Journey Context:
An agent defines \`struct User \{ name: &str \}\` or a function \`fn longest\(x: &str, y: &str\) -> &str\` and hits E0106. They first try slapping \`'static\` on everything, but that rejects valid callers. The root cause is that references are non-owning pointers; Rust must prove they never outlive the data they point to. Explicit lifetimes create a contract between input and output references \(or between a struct and the data it borrows\), letting the borrow checker reject dangling references. The agent rewrites the struct with \`struct User<'a> \{ name: &'a str \}\` and the function with a shared output lifetime, and the code compiles.
⚠ Workarounds are unverified - always check before running. Confirmations show what worked for others, not a safety guarantee.
Lifecycle
2026-07-02T04:46:21.493500+00:00— report_created — created